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Correction...
>>Burning 500 million pounds at 99.9999% destruction removal equivalence
>>(DRE) may release 5,000 pounds of PCBs if the dielectric fluid is one
>>million parts per million; 3,750 pounds of PCBs released at 750,000 ppm,
>>and 2,500 pounds PCBs at 500,000 ppm PCBs. Dielectric fluids range from
>>50% - 100% pure PCBs (or 500,000 - 1,000,000 ppm). We do not need any
>>more PCBs in the air, water, food chain or ecosystems. Incineration will
>>certainly release PCBs since it ain't perfect, and the potential is for
>>far more PCBs to be released than this conservative calculation.
>>99.99999% is based upon a Trial Burn using a surrogate chlorinated
>>compound-NOT PCBs-and this is pie in the sky as far as incineration
>>goes.
>>
>Why would burning PCB waste with 1 PPM PCB release at 99.9999%
>theoretical DRE release more PCB than burning the same amount of PCB waste
>at the same DRE if the waste had 750,000 ppm or 500,000 ppm PCBs
>for theoretical undestroyed PCBs?
I misread the first statement with respect to the question posed above
(didn't see the million after the one). On
100% PCB waste (1,000,000 ppm PCBs), the theoretical undestroyed/emitted
PCB emission on burning 500 million pounds at theoretical DRE is a total
of 50 pounds of PCBs by same methodology in previous message.... not
5000 pounds as claimed on the web site.
500,000,000 pounds = 5 E8 pounds of waste
99.9999% DRE is equivolent to 0.0001% PCB undestroyed/released
0.0001% PCB undestroy/released = 1 E-6 proportion of PCB release during burning
1 ppm PCB content = 1E-6 proportion of PCB in a waste which is 1 PPM PCB
Therefore, for your 1 PPM PCB waste:
In 500,000,000 pounds of 1 PPM PCB waste
there is 5 E8 * 1 E-6 total PCBs
or 500 pounds of PCBs in the waste to be burned.
If these 500 pounds of PCBs are burned with a DRE of 99.9999% then after
incineration there is 5 E 2 * 1 E-6 or 5 E -4 undestroyed or
0.0005 pounds of PCB emitted/undestroyed at 99.9999% theoretical DRE
For your 500,000 ppm PCB waste:
In 500,000,000 pounds of 500,000 ppm PCB waste
there is 5 E8 * 5 E 5 * 1 E-6 total PCBs
or 25 E7 pounds or 250,000,000 pounds of PCB
If these 250,000,000 pounds of PCB are burned with a DRE of 99.9999% then
after incineration there is 2.5 E7 * 1 E-6 or 2.5 E 1 or
25 pounds of PCBs emitted/undestroyed at 99.9999% DRE
The above are theoretical emission rates and do not deal
with PICs, PCDD/F, HCL, etc.
Neil Carman's point about fugitive emissions is a good one.
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